To solve the sum67
problem on CodingBat, you need a clear understanding of how to work with arrays and conditionally sum their elements based on specific rules. This article will walk you through the entire process step by step, helping you develop a solution that meets the requirements of the task.
Understanding the Problem
The goal of the sum67
function is to sum the numbers in an array while ignoring any numbers that are part of a sequence starting with 6
and ending with 7
. In other words, if you encounter a 6
, you ignore all numbers until you find the next 7
.
Problem Breakdown
- Input: An array of integers (e.g.,
[1, 2, 2, 6, 99, 99, 7]
). - Output: The sum of integers in the array, ignoring numbers between
6
and7
(e.g., the sum for the above example would be1 + 2 + 2 = 5
).
Steps to Solve the Problem
Let's break down the steps to create the sum67
function.
Step 1: Initialize Variables
Before you start processing the array, you'll want to initialize a variable to keep track of the total sum and a flag to indicate whether you're in a 6
to 7
sequence.
def sum67(nums):
total = 0
in_skip = False
Step 2: Iterate Through the Array
You need to loop through each element in the nums
array. Use a for
loop to go through the array index by index.
for num in nums:
Step 3: Check for 6
and 7
Within the loop, you will need to check if the current number is a 6
. If it is, set your flag in_skip
to True
to indicate that you should skip subsequent numbers until you find a 7
.
if num == 6:
in_skip = True
elif num == 7 and in_skip:
in_skip = False
Step 4: Sum the Numbers
If the current number is not part of a 6
to 7
sequence (i.e., in_skip
is False
), add the number to your total
.
elif not in_skip:
total += num
Step 5: Return the Result
After finishing the loop, return the total
sum.
return total
Full Function Code
Putting all the steps together, your sum67
function will look like this:
def sum67(nums):
total = 0
in_skip = False
for num in nums:
if num == 6:
in_skip = True
elif num == 7 and in_skip:
in_skip = False
elif not in_skip:
total += num
return total
Example Walkthrough
Let’s see how our function works with an example:
print(sum67([1, 2, 2, 6, 99, 99, 7])) # Output: 5
print(sum67([1, 1, 6, 7, 2])) # Output: 4
print(sum67([1, 6, 2, 2, 7, 7])) # Output: 1
print(sum67([6, 1, 2, 3, 7, 4, 5])) # Output: 15
Explanation of Examples
-
Example 1:
[1, 2, 2, 6, 99, 99, 7]
- Sum:
1 + 2 + 2 = 5
(ignores6
,99
,99
, and7
).
- Sum:
-
Example 2:
[1, 1, 6, 7, 2]
- Sum:
1 + 1 + 2 = 4
(only6
and7
are skipped).
- Sum:
-
Example 3:
[1, 6, 2, 2, 7, 7]
- Sum:
1
(ignores6
,2
,2
,7
).
- Sum:
-
Example 4:
[6, 1, 2, 3, 7, 4, 5]
- Sum:
1 + 2 + 3 + 4 + 5 = 15
(it includes all numbers since they are after the first7
).
- Sum:
Important Notes
- Edge Cases: Remember to handle cases where
6
and7
are absent in the array. - Negative Numbers: Negative numbers should also be considered and summed if they are not between
6
and7
.
Final Thoughts
By breaking down the problem into smaller steps, we've successfully implemented a function to solve the sum67
challenge on CodingBat. This structured approach can be applied to other coding challenges, improving your problem-solving skills.
Happy coding! 🎉